A gas occupies 2240.0 l at 373 k. what are the volumes at standard t...
A gas occupies 2240.0 l at 373 k. what are the volumes at standard temperature answers
Calculating Gas Volume at Standard Temperature
This problem involves calculating the volume of a gas at standard temperature (273 K) given its volume at a different temperature (373 K). We can solve this using Charles's Law, which states that the volume of a gas is directly proportional to its absolute temperature, assuming constant pressure and amount of gas.
Calculations
Charles's Law is expressed mathematically as:
V1/T1 = V2/T2
Where:
- V1 is the initial volume (2240.0 L)
- T1 is the initial temperature (373 K)
- V2 is the final volume (what we want to find)
- T2 is the final temperature (standard temperature, 273 K)
Now, we can plug in the values and solve for V2:
(2240.0 L) / (373 K) = V2 / (273 K) V2 = (2240.0 L * 273 K) / 373 K V2 ≈ 1632.17 L
Answer
Therefore, the volume of the gas at standard temperature (273 K) is approximately 1632.17 L.
Real-World Applications of Charles's Law
Charles's Law is observed in numerous everyday situations. For example, a hot air balloon rises because the air inside is heated, causing it to expand. This increased volume makes the hot air less dense than the surrounding cooler air, creating buoyancy. Similarly, a basketball inflated indoors might feel slightly deflated when taken outside on a cold day because the lower temperature causes the air inside to contract, reducing its volume.
Relationship to Other Gas Laws
Charles's Law is part of the combined gas law, which incorporates Boyle's Law and Gay-Lussac's Law. The combined gas law describes the relationship between pressure, volume, and temperature of a fixed amount of gas. Understanding these relationships is crucial in various fields, including chemistry, physics, and engineering.
FAQ: Common Questions about Gas Laws
Q: What is standard temperature and pressure (STP)?
A: Standard temperature and pressure are standardized conditions used for comparing and measuring gases. STP is typically defined as 0°C (273.15 K) and 1 atm (101.325 kPa).
Q: Why are absolute temperatures (Kelvin) used in gas law calculations?
A: Kelvin is an absolute temperature scale where zero represents the absence of all thermal energy. Using absolute temperature prevents calculations from being affected by negative temperature values, ensuring accurate and meaningful results.
Call to Action: Try practicing more gas law problems with different variables to strengthen your understanding of these fundamental principles!
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